The heat of combustion of solid naphthalene. (C_(10)H_(10)) at constant volume was -4984kJmol^(-1) " at " 298K. Calculate the value of enthalpy change. Given: C_(10)H_(8_((s)))+120_(2_((g)))rarr10CO_(2_((g)))+4H_(2)O_((l)),DeltaU=-4984 kJ.mol^(-1) DeltaU=-4984 kJmol^(-1),R=8.314JK^(-1)mol^(-) T=298K

The heat of combustion of solid naphthalene. (C_(10)H_(10)) at constan

1.	The heat of combustion of solid naphthalene. (C_(10)H_(10)) at constant volume was -4984kJmol^(-1) " at " 298K. Calculate the value of enthalpy change. Given: C_(10)H_(8_((s)))+120_(2_((g)))rarr10CO_(2_((g)))+4H_(2)O_((l)),DeltaU=-4984 kJ.mol^(-1) DeltaU=-4984 kJmol^(-1),R=8.314JK^(-1)mol^(-) T=298K
Answer» SOLUTION :`DELTAN=10-12=-2mol` `DeltaH=DeltaU+Rt(Deltan)` `=-4984xx10^(3)J+8.314Jk^(-1)MOL^(-1)xx298kxx(-2)mol.` `=-4984000J-4955.144J =-4988955.144J` `DeltaH=-4988.955kJ`