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The heat of formation of CO and CO_(2) are -26.4kCaland -94 kCal, respectively. Heat of combustion of carbon monoxide will be |
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Answer» Solution :`C+1//2O_2 to CO "" DeltaH`=-26.4 K.cal …(1) `C+O_2 to CO_2 "" DeltaH`=-94 K.cal …(2) Heat of COMBUSTION of CO is `C+1//2O_2 to CO_2 "" DeltaH`=? EQUATION (1) is reversed . `{:(CO to cancelC+1/cancel2O_2 "" DeltaH="+26.4 K.cal"),(cancelC+cancelO_2to CO_2 "" DeltaH="-94 K.cal" """[Add equation (2)]"):}/(C_((g))+1//2O_(2(g)) to CO_(2(g))""DeltaH="-94 +26.4")` `DeltaH`=-67.6 K.cal |
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