1.

The heat of formation of CO and CO_(2) are -26.4kCaland -94 kCal, respectively. Heat of combustion of carbon monoxide will be

Answer»

Solution :`C+1//2O_2 to CO "" DeltaH`=-26.4 K.cal …(1)
`C+O_2 to CO_2 "" DeltaH`=-94 K.cal …(2)
Heat of COMBUSTION of CO is `C+1//2O_2 to CO_2 "" DeltaH`=?
EQUATION (1) is reversed .
`{:(CO to cancelC+1/cancel2O_2 "" DeltaH="+26.4 K.cal"),(cancelC+cancelO_2to CO_2 "" DeltaH="-94 K.cal" """[Add equation (2)]"):}/(C_((g))+1//2O_(2(g)) to CO_(2(g))""DeltaH="-94 +26.4")`
`DeltaH`=-67.6 K.cal


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