1.

The heat of neutralisation of HCl and NaOH is 57.3 kJ "mol"^(-1). The amount of heat liberated when 0.25 mol of HCl reacts with 1 mol of NaOH is :

Answer»

57.3 kJ
14.325 kJ
28.65kJ
114.6 kJ

SOLUTION :Heat liberated for NEUTRALISATION of 0.5 mol of `H^(+) = 57.3 xx 0.5 = 28.65 kJ`


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