The heat of reaction for an endothermic reaction at constant volume in equilibrium is 1200 cal more than al constant pressure at 300K, then

The heat of reaction for an endothermic reaction at constant volume in

1.	The heat of reaction for an endothermic reaction at constant volume in equilibrium is 1200 cal more than al constant pressure at 300K, then
Answer» <P>`Deltan_((g))= -2` `(K_(P))/(K_(c))=1.648 XX 10^(-3)` `Deltan_((g))= +2` `(K_(c))/(K_(P))=1.648 xx 10^(-3)` Solution :`DeltaU=DeltaH+1200` `DeltaU-DeltaH=1200=Delta n_((g))RT` `Delta n_((g))=(-1200)/(2 xx 300)= -2 implies (Kp)/(Kc)=(RT)^(-2)=(0.0821 xx 300)^(-2)=1.648 xx 10^(-3)`