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The heat of vaporisation of C Cl_(4) at 298 K is 43.0 kJ/"mole". C Cl_(4)(l) to C Cl_(4)(g),DeltaH=43.0 kJ If 1 mole of liquid C Cl_(4) at 298 K has an entropy of 214 J/K , what is the entropy of 1 mole of the vapour in equilibrium with the liquid at this temperature ? |
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Answer» Solution :`DeltaS=(DeltaH_(0))/(T)=(43.0xx10^(3))/(298)=144.3J//molK` But `DeltaS=S_(V)-S_(L)` or `S_(V)=DeltaS+S_(L)=144.3+214=358.3J//molK` |
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