1.

The heats of combustion of graphite and dimond at 298 K are -393 and -395 kJ/ "mole" respectively . The specific heats of these substances are 720 and 505 J kg^(-1)K^(-1) respectively. Calculate the heat of transformation of graphite into diamond at 273 K.

Answer»


Solution :`DELTAH={-393-(395)}+(0.720-0.505)XX(12)/(1000)xx(298-273)]`


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