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The heats of neutralisation of CH_(3)COOH, HCOOH, HCN and H_(2)S are -13.2, -13.4, -2.9 and -3.8 kcal per equivalent respectively. Arrange these acids in increasing order of strength. |
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Answer» Solution :Since we know that the greater the (negative) value of the HEAT of NEUTRALISATION, the more is the strength of the acid, the given acids may be arranged in increasing order of strength as `HCNltH_(2)SltCH_(3)COOHltHCOOH` |
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