The heighsy and horizontal distance x covered by a projectle in a time t seconds are given by the equation y=8t-5t^(2)and x=6t.If x and y are measured the velocity of projection is

The heighsy and horizontal distance x covered by a projectle in a time

1.	The heighsy and horizontal distance x covered by a projectle in a time t seconds are given by the equation y=8t-5t^(2)and x=6t.If x and y are measured the velocity of projection is
Answer» `8 MS^(-1)` `6 ms^(-1)` `14 ms^(-1)` `10MS^(-1)` ANSWER :D