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The height and horizontal distance x of a projectile are given by y=(8t−5t2) m and x=6t m where t is in seconds. Find the maximum height of a projectile.(Take g=10 m/s2) |
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Answer» The height and horizontal distance x of a projectile are given by y=(8t−5t2) m and x=6t m where t is in seconds. Find the maximum height of a projectile. |
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