The height at which the acceleration due to gravity becomes g/9(where g = acceleration due to gravity on the surface of the earth) in terms of R, the radius of the earth is .........

The height at which the acceleration due to gravity becomes g/9(where

1.	The height at which the acceleration due to gravity becomes g/9(where g = acceleration due to gravity on the surface of the earth) in terms of R, the radius of the earth is .........
Answer» `sqrt2R` 2R `R/sqrt2` `R/2` Solution :`IMPLIES` Gravitational ACCELERATION at a HEIGHT from the earth . `g/9 = (GM_e)/((R+H)^2)` `:. (GM_e) /(9R^2) =(GM_e)/((R+h)^2) ""[ :. g = (GM_e)/R^2]` `:. 9R^2 = (R+h)^2` `:. 3R = R + h ` `:. h = 2R`