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| 1. |
The height at which the acceleration due to gravity becomes `(g)/(9)` (where g =the acceleration due to gravity on the surface of the earth) in terms of R, the radius of the earth, is :A. `(R)/(2)`B. `sqrt(2)R`C. 2RD. `(R)/(sqrt(2))` |
| Answer» Correct Answer - C | |