1.

The height of an equilateral triangle measures 9 cm. Find its area, correct to 2 places of decimal. (Take √3 = 1.732)

Answer»

Consider a as the side of an equilateral triangle

We know that

Height of an equilateral triangle = √3/2 a

It is given that height = 9cm

So we get

√3/2 a = 9

On further calculation

a = (9 × 2)/ √3

Multiplying both numerator and denominator by √3

We get

a = (9 × 2 × √3) / (√3 × √3)

So we get

Base = a = 6√3cm

We know that the area of an equilateral triangle = ½ × b × h

By substituting the values

Area of the equilateral triangle = ½ × 6√3 × 9

On further calculation

Area of the equilateral triangle = 27√3 cm2

By substituting the value of √3

Area of the equilateral triangle = 27 × 1.732 = 46.764

By correcting to 2 places of decimal

Area of the equilateral triangle = 46.76 cm2

Therefore, the area of an equilateral triangle = 46.76 cm2.



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