The hemispherical bowl of brass has inner diameter 0.105 m. Find the c

1.	The hemispherical bowl of brass has inner diameter 0.105 m. Find the cost of un-platingit on the inside at the rate of Rs. 16 per 100 cm
Answer» To find the inner cost of plating it, we must find the CSA of the bowl=2πr2radius=0.105m=0.105100 cm=10.5 diameter radius=10.5/2= 5.25now CSA=222/7* 5.25 * 5.25 =173.25cm square cost of tin plating=rs.16 /100cm squarecost for 173.25 cm square =173.25* (1/ 100) *16=27.72thus the cost of tin plating it inside = 27.72 rs

The hemispherical bowl of brass has inner diameter 0.105 m. Find the cost of un-platingit on the inside at the rate of Rs. 16 per 100 cm

Answer»

To find the inner cost of plating it, we must find the CSA of the bowl=2πr2radius=0.105m=0.105*100 cm=10.5 diameter

radius=10.5/2= 5.25now CSA=2*22/7* 5.25 * 5.25

=173.25cm square

cost of tin plating=rs.16 /100cm squarecost for 173.25 cm square =173.25* (1/ 100) *16=27.72thus the cost of tin plating it inside = 27.72 rs