The Henry's law constants for two gases A and B are x and y respectively. The ratio of mole fractions of A to B is 0.2. The ratio of mole fraction of B and A dissolved in water will be

The Henry's law constants for two gases A and B are x and y respective

1.	The Henry's law constants for two gases A and B are x and y respectively. The ratio of mole fractions of A to B is 0.2. The ratio of mole fraction of B and A dissolved in water will be
Answer» `(2x)/y` `(y)/(0.2x)` `(0.2x)/(y)` `(5x)/(y)` Solution :Given , `(K_H)_A = X(K_H)_B = y, (x_A)/(x_B) = 0.2` `((x_B)/(x_A))_("in solution")= ?` `P_A = x(x_A)_("in solution")""…(i)` `P_B = y(x_(B))_("in solution")""…(2)` `((x_B)/(x_A))_("in solution") =(P_B)/(P_A) XX x/y` `= (x_B)/(x_A) xx x/y =1/(0.2)xx x/y = (5x)/y`