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The highest common factor of 117 and another number is 13. The second number cannot be which of the following:1. 1692. 1433. 1564. 130 |
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Answer» Correct Answer - Option 3 : 156 Given: HCF = 13 One number = 117 Concept Used: Number 1 = HCF× (a) Number 2 = HCF× (b) Calculation: Let the ratio of two numbers be a : b here 'a' and 'b' are co-prime numbers. 1st number = 117 and HCF = 13 ⇒ 117 = 13 × a ⇒ a = 9 Now b will be a co-prime number of 9 Now comparing with the options, Option 1 = 169 ⇒ 169 = 13 × b ⇒ b = 13 9 and 13 are co-prime numbers. Hence the second number can be = 169 Now option 2 =143 ⇒ 143 = 13 × b ⇒ b = 11 9 and 11 are co-prime numbers. Hence the second number can be = 143 Now option 4 = 130 ⇒ 130 = 13 × b ⇒ b = 10 9 and 10 are co-prime numbers. Now option 3 = 156 ⇒ 156 = 13 × b ⇒ b = 12 9 and 12 are not co-prime numbers. ∴ 156 cannot be a second number. |
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