1.

The highest excited state that an unexcited hydrogen atom can reach when they are bombarded with12.75 eV of energy is :

Answer»

n=2
n=3
n=4
n=5

Solution :`E_(1)=-13.6eV`
After ABSORPTION of 12.75 eV, energy of electron `=-13.6+12.75=-0.85`
`E_(n)=(E_(1))/(n^(2))impliesn^(2)=(E_(1))/(E_(n))=-(13.6)/(-0.85)=16`
`:.n=4`


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