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The HNH angle is higher than `HPH`, HAsH and HSbH angles - Why ?

Answer» The central atom `epsilon` (where, `epsilon` = N, P, As, Sb, Bi) in all given hydrides is `"Sp"^(3)` hybridized However, its electronegativity decreases and atomic size increase on moving down the group. Therefore is a gradual decrease in the force of repulsion between the shared electron pairs around the central atom. Thus, bond angle decreases as we move down the group.
`{:("Molecule",,"NH"_(3),,"PH"_(3),,"AsH"_(3),,"SbH"_(3),,"BiH"_(3)),("Bondangle",,107.8^(@),,93.6^(@),,91.8^(@),,91.3^(@),,90^(@)):}`


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