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The horizontal range of a projectile fired at an angle of 15° is 50 m. If it is fired with the same speed at an angle of 45°, its range will be(a) 60 m(b) 71 m(c) 100 m(d) 141 m |
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Answer» The horizontal range of a projectile fixed at an angle=15° Range=50m In direct case range=50=u^2/g (sin 2*15°) u^2/2g=50 u^2=100g In 2nd case range=u^2/g(sin 2 *45) =100g/g*1 (sin 90°=1) =100m Option c is correct answer.
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