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The horizontal range of a projectile is R and the maximum height at tained by it is H. A strong windnow begins to blow in the direction of the motion of the projectile, giving it a constant horizontal acceleration = g/2. Under the same conditions of projection, the horizontal range of the projectile will now be:A. `R+H/2`B. `R+H`C. `R+(3H)/2`D. `R+2H` |
Answer» Correct Answer - D |
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