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The hundreds digit of a three-digit number is 7 more than the units digit. The digit of the number are reversed, and the resulting number is subtracted from the original three-digit number. The units digit of the final number so obtained is |
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Answer» Correct Answer - Option 4 : 3 Given: The hundreds digit of a three-digit number = 7 + units digit. Concept: Place value: The digit of any number is called its place value. For example, in the number 256, the place value of 5 is 5. Face value: It is the actual value of any digit in a particular number. For example, in the number 256, the face value of 5 is 50. Any number can be written as the sum of, a product of the face value and place value. for three digit number, abc = 100a + 10b + c Calculation: Let the three-digit number is 'abc' according to question, a = 7 + c ⇒ a - c = 7 .......(1) Now, according to above discussion 'abc' can be written as, abc = 100a + 10b + c ......(2) on reversing the number, we get the new number 'cba' ⇒ cba = 100c + 10b + a ......(3) Substracting equation (2) from (1) abc - cba = ( 100a + 10b + c ) - ( 100c + 10b + a ) abc - cba = 99( a - c ) abc - cba = 99 × 7 = 693 [ from equation (1) ] Hence, unit digit of final number will be 3. |
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