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The hydrated salt `Na_(2)CO_(3)x H_(2)O` undergoes 63 % loss in mass on heating and becomes anhydrous. What is the value of x ? |
Answer» Correct Answer - 10 Molecular mass of `Na_(2)CO_(2)X.H_(2)O=106+18x` Loss in mass due to dehydration = 63 % `(18x xx 100)/(106+18x)=63or(18x)/((106+18x))=0.63` `18x=0.63(100+18x)=66.78+11.34x` `(18 x - 11.34 x)=6.66 x = 66.78` `x=(66.78)/(6.66)~~10`. |
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