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The hydrocarbon which can react with sodium in liquid ammonia isA. `CH_(3)CH_(2)C=C C_(2)CH_(3)`B. `CH_(3)CH_(2)CH_(2)C=C CH_(2)CH_(2)CH_(3)`C. `CH_(3)CH_(2)C=CH`D. `CH_(3)CH=CHCH_(3)` |
Answer» Correct Answer - C Only terminal alkynes react with Na in `NH_(3)` Hence (C ) is correct `CH_(3)CH_(2)Cl-=OH overset(Na//liq NH_(3))to CH_(3)CH_(2)C-=overset(-)(CNa^(+))` |
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