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The hydrocarbon which can react with sodium in liquid ammonia isA. `CH_3CH_2C-=C CH_2CH_3`B. `CH_3CH_2CH_2C-=C CH_2CH_2CH_3`C. `CH_3CH_2C-=CH`D. `CH_3CH=CHCH_3` |
Answer» Correct Answer - C Only terminal alkynes react with Na in liquid `NH_3`. Thus, option (c ) is correct. `CH_3CH_2C-=CH overset(Na//liq. NH_3)to CH_3CH_2C-=C^(-) Na^+` |
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