1.

The hydrogen electrdoe is dipped in a solution of pH=3 at 25^(@)C the potential of the cell would be (the value of 2.303 RT/F is 0.059 V)

Answer»

0.177V
0.087V
`-0.177V`
`0.059V`

Solution :`pH=3`
`therefore [H^(+)]=10^(-3)`
`H^(+)+e^(-)rarr(1)/(2)H_(2)`
`E=E^(@)-(0.059)/(n)"LOG" (1)/([H^(+)])=0-(0.059)/(1)"log"10^(3)`
` E=-0.177V`


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