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The hydrogen electrdoe is dipped in a solution of pH=3 at `25^(@)C` the potential of the cell would be (the value of 2.303 RT/F is 0.059 V)A. 0.177VB. 0.087VC. `-0.177V`D. `0.059V` |
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Answer» Correct Answer - C `pH=3` `therefore [H^(+)]=10^(-3)` `H^(+)+e^(-)rarr(1)/(2)H_(2)` `E=E^(@)-(0.059)/(n)"log" (1)/([H^(+)])=0-(0.059)/(1)"log"10^(3)` ` E=-0.177V` |
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