1.

The hydrogen electrode is dpped in a solution of pH=3 at 25^(@)C. The potential of the cell would be (the value of 2.303RT/F is 0.059V)

Answer»

0.177V
`-0.177V`
`0.087V`
`0.059V`

SOLUTION :REDUCTION POTENTIAL of hydrogen electrode.
`E_(H)=(-2.303RT)/(F)"log"(1)/([H^(+)])`
`=-0.059pH=-0.059xx3=-0.177V`.


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