1.

The hydrogen ion concentration of a 10^(-8) M HCl aqueous solution at 298 K (K_(w)=10^(-14)) is :

Answer»

`1.05xx10^(-7)M`
`9.525xx10^(-8)M`
`1.0xx10^(-8)M`
`1.0xx10^(-6)M`

Solution :`[H^(+)]_("Total")=[H^(+)]_("ACID")+[H^(+)]_("water")`
`[H^(+)]_(HCl)=10^(-8)M`
Let conc. of `H^(+)` from ionisation of water
`[H^(+)]_(H_(2)O)=[OH^(-)]_(H_(2)O)=X`
But `[H^(+)][OH^(-)=1xx10^(-14)`
`(1.0xx10^(-8)+x)(x)=1xx10^(-14)`
`x^(2)+10^(-8)x - 10^(-14)=0`
SOLVING for x, we get `x = 9.5xx10^(-8)`
`THEREFORE [H^(+)]_("total")=1xxx10^(-8)+9.5xx10^(-8)`
`=1.05xx10^(-7)M`.


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