

InterviewSolution
Saved Bookmarks
1. |
The hysterisis loss of a sample of iron is `300Jm^-3 cycl e^-1`. If density of iron is `7500kg//m^3` and mass of iron piece is `15kg`, calculate energy lost/hour when the frequency of magnetisation/demagnetisation used in `50c//s`. |
Answer» Correct Answer - `5*4xx10^4J//hour` Here, energy loss due to hysterisis `=300Jm^-3cycl e^-1` `rho=7500kg//m^3, m=15kg, v=50c//s` Energy lost/hour=? `V=m/rho=(15)/(7500)m^3=2xx10^-3m^3` Energy lost/cycle =`300xx2xx10^-3=0*6` Energy lost/sec`=0*6xx50=30J//s` Energy lost/hour=`30xx60xx60` `=5*4xx10^4J//hr` |
|