The hyterisis loss for a sample of `12kg` is `300Jm^-3cycl e^-1`. If density of iron is `7500kg//m^3`, calculate energy loss per hour at `50cycl e//sec`.

The hyterisis loss for a sample of `12kg` is `300Jm^-3cycl e^-1`. If d

1.	The hyterisis loss for a sample of `12kg` is `300Jm^-3cycl e^-1`. If density of iron is `7500kg//m^3`, calculate energy loss per hour at `50cycl e//sec`.
Answer» Here, energy loss/volume, per cycle `=300Jm^-3cycl e^-1`. Volume of sample `=(mass)/(density)=(12)/(7500)m^3` Total energy loss/cycle`=300xx(12)/(7500)=12/25` Energy loss/ sec `=12/25xx50=24J//sec` Energy loss/hour`=24xx60xx60J=8*64xx10^4J`

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The hyterisis loss for a sample of `12kg` is `300Jm^-3cycl e^-1`. If density of iron is `7500kg//m^3`, calculate energy loss per hour at `50cycl e//sec`.

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