1.

The image of point `P` when viewed from top of the slabs will be A. `2 cm` above PB. `1.5 cm` above PC. `2 cm` below PD. `1 cm` below P

Answer» Correct Answer - D
The two slabs will shift the image a distance
`d = 2 (1 - (1)/(mu)) t = 2 (1 - (1)/(1.5)) (1.5) = 1 cm`


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