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The image of the point (2,7) with respect to line y=x as line of symmmetry please no spam I will mark him or her brainliest who answers first and gives correct answer if gives a spam answer I will report him or her​

Answer» LET A=(2,1) & A′=(5,2)∴The line is mirror.∴ Line is perpendicular to AA′ and PASSES through the midpoint.Slope of AA′=31∴ Slope of mirror=−3∴ EQUATION =(y−23)=−3(x−27)⇒y−23=−3x+221⇒2y−3=−6x+21⇒6x+2y−24=0⇒3x+y−12=0Explanation:I HOPE This Is HELPFUL For You ✌


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