1.

The impact parameter at which the scattering angle is `90^(0) , z=79` and initial energy `10MeV` is

Answer» Correct Answer - C
Given ` theta =90^@,Z=79,e=1.6xx10^(-19)C`,
`E=(1)/(2)mv^2=10MeV=10xx10^6xx1.6xx10^(-19)J`.
`=1.6xx10^(-12)J`
`therefore b=(Ze^2cot(theta/2))/(4piepsilon_0(1/2mv^2))=(9xx10^9xx79xx(1.6xx10^(-19))^2cot45^@)/(1.6xx10^(-12))m`
`=9xx79xx1.6xx10^(-11)m=1137.6xx10^(-11)m`
`=1.1xx10^(-14)m=11fm`


Discussion

No Comment Found

Related InterviewSolutions