1.

The incorrect order indicated against the rate of reaction , aA+bBoverset(h) to C then

Answer»

`-(d[A])/(DT)=a/b xx (d[B])/(dt) `
`-(d[A])/(dt)=b/a xx (d[B])/(dt) `
`-(d[A])/(dt)=-1/2(d[B])/(dt)=+(d[C])/(dt)`
`-(d[A])/(dt)= -b/a xx (d[B])/( dt)=- b/a xx (d[B])/(dt)`

SOLUTION :According to the EXPRESSION `- (1)/(a) xx (d[A])/(dt) = - (1)/(b) (d[B])/(dt) therefore -(d[A])/(dt) = - (a)/(b) (d[B])/(dt)`


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