The incorrect statement for 14 g of `CO` isA. It occupies 2.24 litre at NTPB. It corresponds to `1/2` mole of `CO`C. It corresponds to same mole of `CO` and `N_(2)`D. It corresponds to `3.01xx10^(23)` molecules of `CO`

The incorrect statement for 14 g of `CO` isA. It occupies 2.24 litre a

1.	The incorrect statement for 14 g of `CO` isA. It occupies 2.24 litre at NTPB. It corresponds to `1/2` mole of `CO`C. It corresponds to same mole of `CO` and `N_(2)`D. It corresponds to `3.01xx10^(23)` molecules of `CO`
Answer» Correct Answer - A 14 g of `CO=14/28=0.5` mole 0.5 mole `=3.01xx10^(23)` molecules The molecular weight of `CO=(15+16)=28` The molecular weight of `N_(2)=14+14=28` Therefore, the incorrect statement is that it occupies 2.24 litre at NTP.

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The incorrect statement for 14 g of `CO` isA. It occupies 2.24 litre at NTPB. It corresponds to `1/2` mole of `CO`C. It corresponds to same mole of `CO` and `N_(2)`D. It corresponds to `3.01xx10^(23)` molecules of `CO`

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