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Answer» the first ionization potential of AL is less than the first ionization potential of Mg the SECOND ionization potential of Mg is greater than the second ionization potential of Na the first ionization potential of Na is less than the first ionization potential of Mg The third ionization potential of Mg is greater than the third ionization potential of Al. SOLUTION :`IE_2` of Mg is lower than that of Na because in case of `Mg^(2+)` 3s-ELECTRON has to be REMOVED while in case of `Na^(+)`, an electron from the stable inert gas configruation `(Ne : 2s^2 2p^6)` has to be removed.
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