InterviewSolution
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InterviewSolution
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The increasing d-character in hybridisation of Xe in `XeF_(2), XeF_(4), XeF_(6)` isA. `sp^(2) , sp^(3) d, sp^(3) d^(2)`B. `sp^(3) d, sp^(3) d^(2), sp^(3) d^(3)`C. `sp^(3) d^(2), sp^(3) d, sp^(3) d^(3)`D. `sp^(2), sp^(3), sp^(3) d` |
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Answer» Correct Answer - B `XeF_(2) - sp^(3) d`, Total no. of valence electrons = 22 ` 22/8 = 2 (Q) + 6(R ) , 6/2 = 3 (Q)` ` X = 2 + 3 = 5` Hybridisation is `sp^(3)` d. `XeF_(4) - sp^(3) d^(2)` Total no. of electrons in outermost shells `= 8 + 28 = 36 36/8 = 4 (Q) + 4(R) , 4/2 = 2 (Q) + 0 (R)` ` X = 4 + 2 + 0 = 6` Hybridisation is `sp^(3) d^(2)`. ` XeF_(6) - sp^(3) d^(3)` Total no. of valence electrons = ` 8 + 42 = 50 50/8 = 6 (Q) + 2 2 (R) , 2/2 = 1 (Q) , X = 6 + 1 = 7` Hybridisation is `sp^(3) d^(3)`. |
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