The increasing order of the ionic radii of the given isoelectronic spe

1.	The increasing order of the ionic radii of the given isoelectronic species is :
Answer» `CL^(-),Ca^(2+), K^(+), S^(2-)` `S^(2-), Cl^(-), Ca^(2+), K^(+)` `Ca^(2+), K^(+), Cl^(-), S^(2-)` `K^(+), S^(2-), Ca^(2+), Cl^(-)` Solution : From `Ca^(2+) to K^(+)to Cl^(-) to S^(2-) ` nuclear chaege Z is DECREASING in them are EQUAL 18. THEREFORE the ionic radii of them is increasing.

Discussion