1.

The indicator constant of phenolphthalein is approximately 10^(-8).A solution is prepared by adding 100.01 c.c. of 0..01 N sodium hydroxide to 100.00 c.c. of 0.01 N hydrochloric acid.If a few drops of phenolphthalein are now added.what traction of the indicator is converted to its coloured form ?

Answer»

`1/3`
`3/4`
`1/2`
`9/11`

SOLUTION :millimole, `UNDERSET(100.01xx0.01)(NaOH)underset(" "100xx0.01)(+HCl)toNaCl+H_2O`
So, NaOH left =0.0001
Hence, CONCENTRATION of `OH^(-) =0.0001/200.01=0.0001/200`
`HPhhArr H^+ + Ph^(-)`
`K_a=([H^+][Ph^(-)])/([HPH])`
`implies 10^(-8)=(k_w[Ph])/([OH^(-)][HPh])=((10xx^(-14)xx[Ph])/0.0001)/(200)[HPh], " " ([Ph^(-)])/([HPh])=1/2`
so `([Ph^(-)])/([Ph^(-)]+[HPh])=1/3`


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