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The initial and final temperatures of a liquid in a container are observed to be 75.4 pm 0.5^(@)C and 56.8 pm 0.2^(@)C. Find the fall in the temperature of the liquid. |
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Answer» Solution :`t_(1) = (56.4 PM 0.5)^(@)C , t_(2) = (56.8 pm 0.2)^(@)C` FALL in temperature = `(75.4 pm 0.5^(@)C) - (56.8 pm 0.2^(@)C)` `t = (18.6)^(@)C` |
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