The initial concentratin of `N_(2)O_(5)` in the following first order reaction `N_(2)O_(5)(g) to 2NO_(2)(g)+(1)/(2O_(2))(g) was 1.24 xx10^(-2) mol L^(-1)` at 318K. The concentration of `N_(2)O_(5)` after 60 minutes was `0.20xx10^(-2) mol L^(-1).` Calculate the rate constant of the reaction at 138 K.

The initial concentratin of `N_(2)O_(5)` in the following first order

1.	The initial concentratin of `N_(2)O_(5)` in the following first order reaction `N_(2)O_(5)(g) to 2NO_(2)(g)+(1)/(2O_(2))(g) was 1.24 xx10^(-2) mol L^(-1)` at 318K. The concentration of `N_(2)O_(5)` after 60 minutes was `0.20xx10^(-2) mol L^(-1).` Calculate the rate constant of the reaction at 138 K.
Answer» For a first order reaction `log ""([R]_(1))/([R]_(2))=(k(t_(2)-t_(1)))/(2.303)` `k= (2.303)/((t_(2)- t_(1)))log ""([R_(1)])/([R]_(2))` `=(2.303)/((60 min -0min ))log ""(1.24xx10^(-2)mol L ^(-1))/(0.20xx10^(-2)mol L^(-1))` `=(2.303)/(60)log 6.2 min ^(-1)` `k=0.0304min^(-1).`

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