1.

The initial concentration of N_(2)O_(5) in the first order reactionN_(2)O_(5)to2NO_(2)+1/2O_(2) was 1.24xx10^(-2) mole /lit at 318 k. The concentration of N_(2)O_(5) after 60 min is 0.20xx10^(-2) mole/lt. Calculate the rate constant of reaction at 318 K

Answer»

`0.0304"MIN"^(-1)`
`0.0602"SEC"^(-1)`
`0.0802"sec^(-1)`
`1.265"min"^(-1)`

SOLUTION :`Kxxt=2.303xxlog((C_(0))/(C_(t))),Kxx60=2.303xxlog((1.24xx10^(-2))/(0.20xx10^(-2)))`
`K=2.303/50xxlog(6.2)=2.303//60xx0.7924=0.0304`


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