1.

The initial concentration of N_(2)O_(5) in the following first order reaction N_(2)O_(5)(g) to 2NO_(2)(g) + (1)/(2) O_(2)(g) was 1.24 xx 10^(-2) mol L^(-1) at 318K. The concentration of N_(2)O_(5) after 60 mintues was 0.2 xx10^(-2) mol L^(-1). Calculate the rate constant of the reaction.

Answer»

Solution :DATA : `[R]_(0) = 1.24 xx 10^(-2) molL^(-1)`
`[R] = 0.2 xx 10^(-2) mol L^(-1)`
t = 60 MIN
Formula `K = (2.303)/(t) log ""([R]_(0))/([R])`
` k = (2.303)/(60) log (1.24 xx 10^(-2))/(0.2 xx 10^(2))`
`k = (2.303)/(60) xx log 6.2,`
`k = 0.03 min^(-1)`


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