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The initial concentrations of A and B are same for A +2B harr 3C and when equilibrium concentrations of B and C are same then K_(c) is |
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Answer» 0.25  [B]=[C] `x=a // 5` `K_(C)=([C]^(3))/([A][B]^(2))=(((3A)/(5))^(3))/((4a // 5)(3a // 5)^(2))=(3)/(4)` |
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