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InterviewSolution
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The initial molar concentration of the reactants A and B were 0.1 M and 0.2 M respectively in the following reaction `A+B hArr 2C` When equilibrium was attained the concentration of A in the reaction mixture was found to be 0.06M . Calculate the equilibrium constant. |
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Answer» Correct Answer - `K_(c) =0.67` the number of moles of A initially present =0.1 M `The number of moles of A left =0.06 M `:.` The number of moles of A reacted =0.1 -0.06 =0.04 M According to the equation 0.04 M of A will react with 0.04 M of B to form 0.08 M of C. Therefore , the molar concentration of different species before the reaction and at the equilibrium point is : `{:(,A ,+,B,hArr,2C),("Initial molar conc.",0.1 -0.04,,0.2-0.04,,2xx0.04),("Equilibrium molar conc.",0.06,,0.16,,0.08):}` Applying Law of chemical equilibrium `K_(C)=[[C]^(2)]/[[A][B]]=(0.08 xx 0.08)/(0.06xx0.16)=0.67` |
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