The initial phase of body executing SHM is (pi)/(4), then what will be its phase at the end of 10 oscillations?

The initial phase of body executing SHM is (pi)/(4), then what will be

1.	The initial phase of body executing SHM is (pi)/(4), then what will be its phase at the end of 10 oscillations?
Answer» Solution :`IMPLIES theta = 2 PI eta + phi` `= 2pi xx 10 +(pi)/(4)` `= 20pi +(pi)/(4)` `= (81pi)/(4)RAD`.