The initial rates of reaction 3" A"+2" B"+" C"to Products, at different initial concentrations are given below : {:("Initial rate, "Ms^(-1),,,[A]_(0)","M,,,[B]_(0)","M,,,[C]_(0)","M),(5.0xx10^(-3),,,0.010,,,0.005,,,0.010),(5.0xx10^(-3),,,0.010,,,0.005,,,0.015),(1.0xx10^(-2),,,0.010,,,0.010,,,0.010),(1.25xx10^(-3),,,0.005,,,0.005,,,0.010):} The order with respect to the reactants A, B and C are respectively

The initial rates of reaction 3" A"+2" B"+" C"to Products, at differen

1.	The initial rates of reaction 3" A"+2" B"+" C"to Products, at different initial concentrations are given below : {:("Initial rate, "Ms^(-1),,,[A]_(0)","M,,,[B]_(0)","M,,,[C]_(0)","M),(5.0xx10^(-3),,,0.010,,,0.005,,,0.010),(5.0xx10^(-3),,,0.010,,,0.005,,,0.015),(1.0xx10^(-2),,,0.010,,,0.010,,,0.010),(1.25xx10^(-3),,,0.005,,,0.005,,,0.010):} The order with respect to the reactants A, B and C are respectively
Answer» `3, 2, 0` `3, 2, 1` `2, 2, 0` `2, 1, 0` Solution :SUPPOSE order w.r.t. A, B and C are `alpha, beta and gamma` respectively. Then `50 xx 10^(-3) = (0010)^(alpha) (0.005)^(beta) (0.010)^(gamma)""…(i)` `50 xx 10^(-3) = (010)^(alpha)(0.005)^(beta) (0015)^(gamma)""…(ii)` `10 xx 10^(-2) = (0010)^(alpha) (0010)^(beta) (0.010)^(gamma) ""...(iii)` `125 xx 10^(-3) = (0005)^(alpha)(0.005)^(beta) (0.010)^(gamma)""...(iv)` Dividing (i) by (ii) 1=((0010)/(0015))^(gamma)or((2)/(3))^(gamma)=1=((2)/(3))^(0)thereforegamma=0` Dividing (iii) by (ii), `(10 xx 10^(-2))/(50 xx 10^(-3)) = (2)^(beta) ((2)/(3))^(gamma) or 2 = (2)^(beta) ((2)/(3))^(0) = 2^(beta)` or `2^(beta) = 2 or beta =1.` Dividing (i) by (iv), 4 = `(2)^(alpha) or alpha = 2 ` `therefore` Orders w.r.t. A , B and C are 2, 1, 0.