1.

The initial ratio of hydrolysis of methyl acetate (1 M) by a weak acid (HA, 1M) is 1//100^(th) of that of a strong acid (HX, 1M) at 25^(@)C. The K_(a) of HA is

Answer»

`1 xx 10^(-4)`
`1 xx 10^(-5)`
`1 xx 10^(-6)`
`1 xx 10^(-3)`

Solution :As ester hydrolysis is first order with RESPECT to `[H^(+)]`.
`(R_(HA))/(R_(HA)) = ([H^(+)]_(HA))/([H^(+)]_(HX))`
`(1)/(100) = [H^(+)]_(HA)`
`{:(HA,H^(+),+,A^(-)),(1-0.01,0.01,0.01,),(~~1,,,):}`
`K_(a) = (0.01 xx 0.01)/(1) = 10^(-4)`


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