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The initial speed of a body of mass 2.0 kg is 5.0 ms^(-1) a force fro 4s in the direction of motion of the body the force timegraph is shown in the diagram calculate the impulse of the forceand the finalspeed of the body |
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Answer» SOLUTION :Givenmass = 2.0 KG Initialspeed =5.0 `ms^(-1)`  Formula IMPULSE of a force  `=(1)/(2) xx 1.5 xx 3 + 1 xx 3 + (1)/(2)` `=(1)/(2) xx 4.5+ 3 + (1)/(2)xx 5 xx 0.5 +2` `=2.25 + 3+ 1.25 + 2= 8.50 Ns` As Impulse = changein momentum `=mDelta v` Changeinvelocity `Delta v = ("impulse")/( m ) = (8.50)/(2) ` Finalspeedof thebodyInitialspeed`+Delta v = 5.0+ 4.25 = 9.25 ms^(-1)` |
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