The initial temperature of a gas 1s 27 to temperature 80 cm^(3) of the gas should be heated to increases the volume by 25%.

The initial temperature of a gas 1s 27 to temperature 80 cm^(3) of the

1.	The initial temperature of a gas 1s 27 to temperature 80 cm^(3) of the gas should be heated to increases the volume by 25%.
Answer» Solution :`v_(1)80 cm^(3), v_(2)+80+(25)/(100)xx80=100 cm^(3)` `T_(1)=27+273=300 K, T_(2)=?` `(v_(1))/(T_(1))=(v_(2))/(T_(2)) orT_(2)=(T_(1)V_(2))/(V_(1))=(300xx100)/(80)` `:. T_(2) =375 K=375-273=102^(@)C` `:. T_(2)=102^(@)C` `:. T_(2)=102^(@)C`