The instantaneous angular position of a point on a rotating wheel is given by the equationtheta (t) = 2t^3 - 6t^2 .The torque on the wheel becomes zero at : .......... .

The instantaneous angular position of a point on a rotating wheel is g

1.	The instantaneous angular position of a point on a rotating wheel is given by the equationtheta (t) = 2t^3 - 6t^2 .The torque on the wheel becomes zero at : .......... .
Answer» `t = 1s` `t = 0.5 s` `t= 0.25 s ` `t =2s` Solution :According to equation , TORQUE ` TAU = 0` it means that ` PROP = (d^2)/( dt^2)` here ,` THETA = 2t^3 - 6t^2` ` alpha = (d^2)/(dt^2) (2t^3 - 6t^2) = 12T = 12` ` [ prop= (d^2 t)/(dt^2) = 0 ] = 12t - 12 = 0` ` therefore t = 1s `